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5n^2-38n-16=0
a = 5; b = -38; c = -16;
Δ = b2-4ac
Δ = -382-4·5·(-16)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-42}{2*5}=\frac{-4}{10} =-2/5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+42}{2*5}=\frac{80}{10} =8 $
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